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More Examples – Pythagorean Formula

On this page, we practice using the Pythagorean formula to find missing sides in right triangles.

We practice:

  • finding the hypotenuse
  • finding a missing side
  • working with larger numbers
  • simplifying square roots

Remember

The Pythagorean formula is:


\(c^2=a^2+b^2\)

Where:

  • \(c\) is the hypotenuse.
  • The hypotenuse is the longest side.
  • The hypotenuse is opposite the \(90^\circ\) angle.
  • \(a\) and \(b\) are the other two sides of the right triangle.

To find the hypotenuse, add the squares of the two known sides.

To find another missing side, subtract the square of the known side from the square of the hypotenuse.

Example 1 – Find the Hypotenuse

Find the hypotenuse \(x\) of the right triangle.

The two known sides are \(3\) and \(4\).

Solution:


\(x^2=3^2+4^2\)


\(x^2=9+16\)


\(x^2=25\)

Take the square root of both sides:

\(x=\sqrt{25}\)

\(x=5\)

So, the hypotenuse is \(5\).

Example 2 – Find a Missing Side

Find the missing side \(x\) of the right triangle.

Hypotenuse \(=5\)

Known side \(=4\)

Solution:


\(5^2=x^2+4^2\)

\(25=x^2+16\)

Subtract \(16\) from both sides:

\(x^2=9\)

Take the square root of both sides:

\(x=\sqrt{9}\)

\(x=3\)

So, the missing side is \(3\).

Example 3 – Find a Missing Side

Find the missing side \(x\) of the right triangle.

Hypotenuse \(=13\)

Known side \(=5\)

Solution:


\(13^2=x^2+5^2\)

\(169=x^2+25\)

Subtract \(25\) from both sides:

\(x^2=144\)

Take the square root of both sides:


\(x=\sqrt{144}\)

\(x=12\)

So, the missing side is \(12\).

Example 4 – Find the Hypotenuse

Find the hypotenuse \(x\) of the right triangle.

The two known sides are \(8\) and \(15\).

Solution:


\(x^2=8^2+15^2\)

\(x^2=64+225\)

\(x^2=289\)

Take the square root of both sides:

\(x=\sqrt{289}\)

\(x=17\)

So, the hypotenuse is \(17\).

Example 5 – Find the Hypotenuse

Find the hypotenuse \(y\) of the right triangle.

The two known sides are \(1\) and \(1\).

Solution:

\(y^2=1^2+1^2\)

\(y^2=1+1\)

\(y^2=2\)

Take the square root of both sides:

\(y=\sqrt{2}\)

As a decimal:

\(y \approx 1.41\)

So, the hypotenuse is:

\(\sqrt{2} \approx 1.41\)

Practice

  • More Examples (Current page)
  • Take the Quiz

Continue Learning

  1. Pythagorean Formula
  2. Pythagoras Theorem (a² + b² = c²) – Visual Proof 1
  3. Pythagoras Theorem (a² + b² = c²) – Visual Proof 2
  4. Pythagoras Theorem (Example)

Navigation

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  • Back to Triangles
  • Back to Home

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