Skip to content

Mulkek

Math is simple

Menu
  • Home
  • About
  • All Lessons
  • Coordinate Geometry
  • Pythagorean Theorem
  • Triangles
  • Polygons
  • Circle
  • Algebra, Calculus, and Trigonometry
  • Contact Us
  • Privacy Policy
  • Cookie Policy

More Examples – Sum of Interior Angles of a Polygon (Proof)

Explanation

In this page, we practice finding the sum of the interior angles of different polygons.

Remember:

A polygon can be split into triangles.

Since each triangle has an angle sum of \(180^\circ\), we can use the number of triangles inside the polygon to find the total sum of the interior angles.

For a polygon with \(n\) sides, the number of triangles is:

\(n − 2\)

So, the formula is:

Sum of Interior Angles \(= (n − 2) × 180^\circ\)

Formula / Rule

Sum of Interior Angles \(= (n − 2) × 180^\circ\)

where:

\(n\) is the number of sides of the polygon.

Example 1

Find the sum of the interior angles of a quadrilateral.

A quadrilateral has 4 sides, so:

\(n = 4\)

Use the formula:

Sum of Interior Angles \(= (n − 2) × 180^\circ\)

Substitute \(n = 4\):

Sum of Interior Angles \(= (4 − 2) × 180^\circ\)

\(= 2 × 180^\circ\)

\(= 360^\circ\)

So, the sum of the interior angles of a quadrilateral is:

\(360^\circ\)

Example 2

Find the sum of the interior angles of a pentagon.

A pentagon has 5 sides, so:

\(n = 5\)

Use the formula:

Sum of Interior Angles \(= (n − 2) × 180^\circ\)

Substitute \(n = 5\):

Sum of Interior Angles \(= (5 − 2) × 180^\circ\)

\(= 3 × 180^\circ\)

\(= 540^\circ\)

So, the sum of the interior angles of a pentagon is:

\(540^\circ\)

Example 3

Find the sum of the interior angles of a hexagon.

A hexagon has \(6\) sides, so:

\(n = 6\)

Use the formula:

Sum of Interior Angles \(= (n − 2) × 180^\circ\)

Substitute \(n = 6\):

Sum of Interior Angles \(= (6 − 2) × 180^\circ\)

\(= 4 × 180^\circ\)

\(= 720^\circ\)

So, the sum of the interior angles of a hexagon is:

\(720^\circ\)

Example 4

Find the sum of the interior angles of a \(1002\)–sided polygon.

A \(1002\)–sided polygon has \(1002\) sides, so:

\(n = 1002\)

Use the formula:

Sum of Interior Angles \(= (n − 2) × 180^\circ\)

Substitute \(n = 1002\):

Sum of Interior Angles \(= (1002 − 2) × 180^\circ\)

\(= 1000 × 180^\circ\)

\(= 180,000^\circ\)

So, the sum of the interior angles of a \(1002\)–sided polygon is:

\(180,000^\circ\)

Practice

  • More Examples (Current page)
  • Take the Quiz

Continue Learning

  1. Sum of Interior Angles of a Polygon (Proof)
  2. Find Missing Interior Angles of a Polygon (Examples)
  3. Why Regular and Irregular Polygons Have Different Angle Formulas?

Navigation

  • Back to Polygons
  • Back to Home

© Mulkek 2026. Powered by WordPress

Manage Consent

We use essential cookies and may use third-party services such as YouTube and advertising partners. You can manage your preferences at any time.

Functional Always active
These cookies are necessary for the website to function properly and cannot be disabled.
Preferences
These cookies store your preferences, such as consent settings.
Statistics
The technical storage or access that is used exclusively for statistical purposes. We do not currently use statistical tracking cookies.
Marketing
These cookies are used to display advertisements and enable embedded services such as YouTube videos. They may be used to personalize ads and measure their performance.
  • Manage options
  • Manage services
  • Manage {vendor_count} vendors
  • Read more about these purposes
View preferences
  • {title}
  • {title}
  • {title}