Test your understanding of \(\pi\), circumference, diameter, and curved distances in circles.
Try to answer the questions before checking the answers at the bottom of the page.
Question 1
What does \(\pi\) represent?
A) Radius divided by diameter
B) Circumference divided by diameter
C) Diameter divided by radius
Question 2
What is the approximate value of \(\pi\)?
A) \(2.14\)
B) \(3.14\)
C) \(4.14\)
Question 3
What is the circumference formula using diameter?
A) \(C=D + \pi\)
B) \(C=\pi D\)
C) \(C=\frac{\pi}{D}\)
Question 4
A circle has diameter:
\(D=10 \text{ m}\)
Using:
\(\pi \approx 3.14\)
find the circumference.
A) \(31.4 \text{ m}\)
B) \(20 \text{ m}\)
C) \(15.7 \text{ m}\)
Question 5
A circle has circumference:
\(C=100 \text{ m}\)
What is the semicircle distance?
A) \(25 \text{ m}\)
B) \(50 \text{ m}\)
C) \(100 \text{ m}\)
Question 6
Which formula gives the circumference using the radius?
A) \(C=\pi r\)
B) \(C=2\pi r\)
C) \(C=\pi r^2\)
Question 7
A circle has radius:
\(r=5\text{ cm}\)
What is its diameter?
A) \(5\text{ cm}\)
B) \(10\text{ cm}\)
C) \(25\text{ cm}\)
Question 8
A circle has diameter:
\(D=8\text{ m}\)
Using:
\(\pi\approx3.14\)
find the circumference.
A) \(12.56\text{ m}\)
B) \(25.12\text{ m}\)
C) \(50.24\text{ m}\)
Question 9
A circle has circumference:
\(C=62.8\text{ cm}\)
Using:
\(\pi\approx3.14\)
find the diameter.
A) \(10\text{ cm}\)
B) \(20\text{ cm}\)
C) \(31.4\text{ cm}\)
Question 10
Why does every circle have the same value of \(\pi\)?
A) The circumference and diameter increase in the same ratio.
B) Every circle has the same diameter.
C) Every circle has the same circumference.
Answers
- B) Circumference divided by diameter
- B) \(3.14\)
- B) \(C=\pi D\)
- A) \(31.4 \text{ m}\)
- B) \(50 \text{ m}\)
- B) \(C=2\pi r\)
- B) \(10\text{ cm}\)
- B) \(25.12\text{ m}\)
- B) \(20\text{ cm}\)
- A) The circumference and diameter increase in the same ratio.
Practice
- More Examples
- Take the Quiz (Current page)
Continue Learning
- What is \(\pi\) (pi)? An Easy Explanation
- Why the Area of a Circle is \(\pi r^2\) (Visual Explanation)